Proportion Chapter 1 Exercise 1B CA Foundation maths solutions
Mathematics CA foundation textbook chapter 1 Ratio and Proportion, Indices, Logarithms Exercise 1B solutions are given.
You should study the textbook lesson chapter 1.
You should observe example problems which are given in the textbook.
Ratio and Proportions, Indices, Logarithms
Exercise 1B C.A. Foundation maths solutions Proportion Chapter 1
CA foundation maths solutions
Chapter 1
Proportion
Exercise 1B
Problem 1
The fourth proportional to 4, 6, 8 is
Problem 2
The third proportional to 12, 18 is
Problem 3
The mean proportional between 25, 81 is
Problem 4
The number which has the same ratio to 26 that 6 has to 13 is
Problem 5
The fourth proportional to 2a,a², c is
Problem 6
If four numbers 1/2, 1/3, 1/5, 1/x are proportional then x is
Problem 7
The mean proportional between 12x² and 27y² is
(Hint : Let k be the mean proportional)
Problem 8
If A =B/2 = C/2, then A : B : C is
Problem 9
If a/3 = b/4 = c/7, then a + b + c / c is
Problem 10
If p/q = r/s = 2.5/1.5, the value of ps : qr is
Problem 11
If x: y = z : w = 2.5 : 1.5, the value of (x + y)/(y + w) is
Problem 12
If (5x – 3y) / (5 – 3x) = 3/4, the value of x : y is
Problem 13
If A : B = 3:2 and B : C = 3 : 5, then A : B : C is
Problem 14
If x/2 = y/2 = z/7, then the value of (2x – 5 + 4z)/2y is
Problem 15
If x : y = 2 : 3, y : z = 4 : 3 then x : y : z is
Chapter 1 Proportion CA Foundation maths solutions Exercise 1B
C.A. foundation maths solutions
Chapter 1
Ratio and Proportions, Indices, Logarithms
Exercise 1B
Problem 16
Division of ₹ 750 into 3 parts in the ratio 4 : 5 : 6 is
Problem 17
The sum of the ages of 3 persons is 150 years ago their ages were in the ratio 7 : 8 : 9. Their present ages are
Problem 18
The numbers 14, 16, 35, 42 are not in proportion. The fourth term for which they will be in proportion is
Problem 19
If x/y = z/w, implies y/x = w/z, then the process is called
Problem 20
If p/q = r/s = p – r/q – s, the process is called
Problem 21
If a/b = c/d, implies (a + b)/(a – b) = (c + d)/(c – d), the process is called
Problem 22
If u/v= w/p, then (u – v)/(u + v) = (w – p)/(w + p). The process is called
Problem 23
12, 16, star, 20 are in proportion. Then star is
Problem 24
4, star, 9, 13 1/2 are in proportion. Then star is
Problem 25
The mean proportional between 1.4 gms and 5.6 gms is
Problem 26
If a/4 = b/5 = c/9 then (a + b+ c)/c is
Problem 27
Two numbers are in the ratio 3 : 4; if 6 be added to each terms of the ratio, then the new ratio will be 4 : 5, then the numbers are
Problem 28
If a/4 = b/5 then
Problem 29
If a : b = 4 : 1 then √a/√b + √b /√a is
Problem 30
If x/(b + c – a) = y/(c + a – b) = z/(a + b – c) then ( b – c)x + ( c – a)y + ( a – b)z is
Note : You should observe the solutions. You will be try them in your own method.
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