# Proportion Chapter 1 Exercise 1B CA Foundation maths solutions

Mathematics CA foundation textbook chapter 1 Ratio and Proportion, Indices, Logarithms Exercise 1B solutions are given.

You should study the textbook lesson chapter 1.

You should observe example problems which are given in the textbook.

CA foundation maths solutions

Ratio and Proportions, Indices, Logarithms

Exercise 1A

Exercise 1B

Exercise 1C

Exercise 1D

## Exercise 1B C.A. Foundation maths solutions Proportion Chapter 1

CA foundation maths solutions

Chapter 1

Proportion

Exercise 1B

Problem 1

The fourth proportional to 4, 6, 8 is

Problem 2

The third proportional to 12, 18 is

Problem 3

The mean proportional between 25, 81 is

Problem 4
The number which has the same ratio to 26 that 6 has to 13 is

Problem 5

The fourth proportional to 2a,a², c is

Problem 6

If four numbers 1/2, 1/3, 1/5, 1/x are proportional then x is

Problem 7

The mean proportional between 12 and 27y² is

(Hint : Let k be the mean proportional)

Problem 8

If A =B/2 = C/2, then A : B : C is

Problem 9

If a/3 = b/4 = c/7, then a + b + c / c  is

Problem 10

If p/q = r/s = 2.5/1.5, the value of ps : qr is

Problem 11

If x: y = z : w = 2.5 : 1.5, the value of (x + y)/(y + w) is

Problem 12

If (5x – 3y) / (5 – 3x) = 3/4, the value of x : y is

Problem 13

If A : B = 3:2 and B : C = 3 : 5, then A : B : C is

Problem 14

If x/2 = y/2 = z/7, then the value of (2x – 5 + 4z)/2y is

Problem 15

If x : y = 2 : 3, y : z = 4 : 3 then x : y : z is

### Chapter 1 Proportion CA Foundation maths solutions Exercise 1B

C.A. foundation maths solutions

Chapter 1

Ratio and Proportions, Indices, Logarithms

Exercise 1B

Problem 16

Division of ₹ 750 into 3 parts in the ratio 4 : 5 : 6 is

Problem 17

The sum of the ages of 3 persons is 150 years ago their ages were in the ratio 7 : 8 : 9. Their present ages are

Problem 18

The numbers 14, 16, 35, 42 are not in proportion. The fourth term for which they will be in proportion is

Problem 19

If x/y = z/w, implies y/x = w/z, then the process is called

Problem 20

If p/q = r/s = p – r/q – s, the process is called

Problem 21

If a/b = c/d, implies (a + b)/(a – b) = (c + d)/(c – d), the process is called

Problem 22

If u/v= w/p, then (u – v)/(u + v) = (w – p)/(w + p). The process is called

Problem 23

12, 16, star, 20 are in proportion. Then star is

Problem 24

4, star, 9, 13 1/2 are in proportion. Then star is

Problem 25

The mean proportional between 1.4 gms and 5.6 gms is

Problem 26

If a/4 = b/5 = c/9 then (a + b+ c)/c is

Problem 27

Two numbers are in the ratio 3 : 4; if 6 be added to each terms of the ratio, then the new ratio will be 4 : 5, then the numbers are

Problem 28

If a/4 = b/5 then

Problem 29

If a : b = 4 : 1 then √a/√b + √b /√a is

Problem 30

If x/(b + c – a) = y/(c + a – b) = z/(a + b – c) then ( b – c)x + ( c – a)y + ( a – b)z is

Note : You should observe the solutions. You will be try them in your own method.

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