NCERT solutions Class 6 maths Knowing our Numbers exercise 1.2
CERT maths class 6 chapter 1 Knowing our numbers exercise 1.2 solutions are given. You should study the textbook lesson Knowing our Numbers class 6 maths very well. You should also observe and practice all example problems and solutions given in the textbook. Observe the given solutions and try them in your own method. NCERT maths class 6 solutions Exercise 1.1 Exercise 1.2Exercise 1.2 Knowing our Numbers maths class 6 NCERT solutions
Class 6 maths Chapter 1 Knowing our Numbers Exercise 1.2 Problem 1 6th class maths textbook chapter 1 Knowing our Numbers exercise 1.2 problem 11. A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all the four days.
2. Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need.
Solution: The number of runs Shekhar scored = 6980 The number of runs he wishes to complete = 10,000 The number of runs he required. = 10,000 – 6980. = 3020 Therefore, he needs 3020 more runs. 6th class maths textbook chapter 1 Knowing our Numbers exercise 1.2 problem 33. In an election, the successful candidate registered 5,77,500. votes and his nearest rival second 3,48,700. votes. By what margin did the successful candidate win the election?
4. Kirti bookstore sold books worth Rs. 2,85,891 in the first week of June and books worth Rs. 4,00,786 in the week of the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?
Solution: The worth of books sold in the first week = Rs. 2,85,891 The worth of books sold in the second week = Rs. 4,00,786 The worth of total books sold in two weeks = Rs.2,85,891 + Rs. 4,00,768 =Rs.6,86,659 Therefore, sale of second week is greater than that of first week. The worth of more books sold in the second week = Rs. 4,00,768 – Rs. 2,85,891 = Rs. 1,14,877 Therefore, the worth of Rs. 1,14,877 books were sold in the second week. 6th CBSE maths chapter 1 Knowing our Numbers exercise 1.2 problem 55. Find the difference between the greatest and the least number that can be written using the digits 6, 2, 7, 4, 3 each only once.
Solution: Using the digits 6, 2, 7, 4, 3 The greatest five-digit number = 76,432 The smallest five-digit number = 23,467 The difference between the greatest and smallest number = 76,432 -23,467 = 52,965 Therefore, the difference is 52,965. 6th CBSE maths chapter 1 Knowing our Numbers exercise 1.2 problem 66. A machine, on an average, manufactures 2,825 screws a day. How many screws did it produce in the month of January 2006?
7. A merchant had Rs. 78,592 with her. She placed an order for purchasing 40 radio sets at Rs.1,200 each. How much money will remain with her after the purchase?
Solution: The cost of one radio set = Rs. 1,200 The cost of 40 radio sets = Rs. 1,200 × 40 = Rs. 48,000 The merchant contained the money = Rs.78,592 She spent the money for purchasing radio sets = Rs. 48,000 She contains the money after the purchase = Rs. 78,592 – Rs. 48,000 = Rs. 30,592 Therefore, Rs. 30,592 will remain with her after the purchase. CBSE class 6 maths chapter 1 Knowing our Numbers exercise 1.2 problem 88. A student multiplied 7236 by 65 instead of multiplying by 56. By how much was his answer greater than the correct answer?
Solution: The multiplication done by the student = 7236 × 65 = 470,340 The multiplication required by the student = 7236 × 56 = 4,05,216 The difference between the multiplications = 4,70,340 – 4,05,516 = 65,124 Therefore, 65,124 is greater than the correct answer. CBSE class 6 maths chapter 1 Knowing our Numbers exercise 1.2 problem 99. To stitch a shirt, 2m 15 cm cloth is needed. Out of 40m cloth, how many shirts can be stitched and how much cloth will remain?
Solution: The cloth needed to stitch one shirt = 2 m 15 cm = 215 cm Length of the cloth = 40 m = 4000 cm The number of shirts can be stitched = 4000 ÷ 215 [ 4000 /215 = 18 and the remainder130] Therefore, 18 shirts can be stitched and 130 cm or 1m 30 cm will remain. 6th class maths chapter 1 Knowing our Numbers exercise 1.2 problem 1010. Medicine is packed in boxes, each weighing 4 kg 500 g. How many such boxes can be loaded in a van which cannot carry beyond 800 kg?
Solution: The weight of one box = 4 kg 500g = 4500 g Maximum weight can be loaded in a van = 800 kg = 800000 g The number of boxes can be loaded = 800000 g ÷ 4500 g [ 8,00,000/4,500 = 177 and the remainder 3,500] Therefore, 177 boxes can be loaded in the van. 6th class maths chapter 1 Knowing our Numbers exercise 1.2 problem 1111. The distance between the school and the house of a student’s house is 1 km 875 m. Everyday she walks both ways. Find the total distance covered by her in six days.
Solution: The distance between the school and the house of a student = 1 km 875 m = 1875 m The distance between the house and school of the student = 1875 m The total distance covered in one day = 1875 + 1875 = 3750 m The distance covered in six days = 3750 m × 6 = 22500 m= 22 km 500 m (22500 ÷ 1000 = 22.5) Therefore, 22 km 500m distance covered by her in six days. 6th class maths chapter 1 Knowing our Numbers exercise 1.2 problem 1212. A vessel has 4 litres and 500 ml of curd. In how many glasses, each of 25 ml capacity, can it be filled?
Solution: The quantity of curd in a vessel = 4 litres 500 ml= 4500 ml The capacity of one glass = 25 ml The number of glasses can be filled = 4500 ÷ 25 = 180 Therefore, 180 glasses can be filled by curd. Note: Observe the solutions and try them in your own method. Inter maths solutions SSC maths class 10 solutions NCERT class 7 maths solutions NCERT class 8 chapter exercise 3.3 solutions